(x^2+1)+(-4x^2+5)=

Solution for (x^2+1)+(-4x^2+5)= equation:

Simplifying
(x2 + 1) + (-4x2 + 5) = 0

Reorder the terms:
(1 + x2) + (-4x2 + 5) = 0

Remove parenthesis around (1 + x2)
1 + x2 + (-4x2 + 5) = 0

Reorder the terms:
1 + x2 + (5 + -4x2) = 0

Remove parenthesis around (5 + -4x2)
1 + x2 + 5 + -4x2 = 0

Reorder the terms:
1 + 5 + x2 + -4x2 = 0

Combine like terms: 1 + 5 = 6
6 + x2 + -4x2 = 0

Combine like terms: x2 + -4x2 = -3x2
6 + -3x2 = 0

Solving
6 + -3x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -3x2 = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -3x2 = 0 + -6
-3x2 = 0 + -6

Combine like terms: 0 + -6 = -6
-3x2 = -6

Divide each side by '-3'.
x2 = 2

Simplifying
x2 = 2

Take the square root of each side:
x = {-1.414213562, 1.414213562}